Base | Representation |
---|---|
bin | 10011110010111110110… |
… | …010011010000010101001 |
3 | 11211001110100110101022021 |
4 | 103302332302122002221 |
5 | 134242110100103231 |
6 | 2520544115224441 |
7 | 200200145612215 |
oct | 23627662320251 |
9 | 4731410411267 |
10 | 1360410550441 |
11 | 484a46320938 |
12 | 19b7a68a8121 |
13 | 9b39491b187 |
14 | 49bb678b945 |
15 | 255c2722811 |
hex | 13cbec9a0a9 |
1360410550441 has 2 divisors, whose sum is σ = 1360410550442. Its totient is φ = 1360410550440.
The previous prime is 1360410550399. The next prime is 1360410550489. The reversal of 1360410550441 is 1440550140631.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 699278940441 + 661131610000 = 836229^2 + 813100^2 .
It is a cyclic number.
It is not a de Polignac number, because 1360410550441 - 221 = 1360408453289 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1360410550397 and 1360410550406.
It is not a weakly prime, because it can be changed into another prime (1360410550141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680205275220 + 680205275221.
It is an arithmetic number, because the mean of its divisors is an integer number (680205275221).
Almost surely, 21360410550441 is an apocalyptic number.
It is an amenable number.
1360410550441 is a deficient number, since it is larger than the sum of its proper divisors (1).
1360410550441 is an equidigital number, since it uses as much as digits as its factorization.
1360410550441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28800, while the sum is 34.
The spelling of 1360410550441 in words is "one trillion, three hundred sixty billion, four hundred ten million, five hundred fifty thousand, four hundred forty-one".
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