Base | Representation |
---|---|
bin | 111111010110010101… |
… | …1110000000101001001 |
3 | 111000010221101202220112 |
4 | 1332230223300011021 |
5 | 4212103012331312 |
6 | 142255121404105 |
7 | 12554140403042 |
oct | 1765453600511 |
9 | 430127352815 |
10 | 136041136457 |
11 | 52770747396 |
12 | 22447a99635 |
13 | caa06444a5 |
14 | 68279458c9 |
15 | 38133c4d22 |
hex | 1facaf0149 |
136041136457 has 2 divisors, whose sum is σ = 136041136458. Its totient is φ = 136041136456.
The previous prime is 136041136453. The next prime is 136041136463. The reversal of 136041136457 is 754631140631.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 75399118921 + 60642017536 = 274589^2 + 246256^2 .
It is a cyclic number.
It is not a de Polignac number, because 136041136457 - 22 = 136041136453 is a prime.
It is not a weakly prime, because it can be changed into another prime (136041136453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68020568228 + 68020568229.
It is an arithmetic number, because the mean of its divisors is an integer number (68020568229).
Almost surely, 2136041136457 is an apocalyptic number.
It is an amenable number.
136041136457 is a deficient number, since it is larger than the sum of its proper divisors (1).
136041136457 is an equidigital number, since it uses as much as digits as its factorization.
136041136457 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 181440, while the sum is 41.
The spelling of 136041136457 in words is "one hundred thirty-six billion, forty-one million, one hundred thirty-six thousand, four hundred fifty-seven".
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