Base | Representation |
---|---|
bin | 111111010110011010… |
… | …0111100011011101011 |
3 | 111000011002221012122201 |
4 | 1332230310330123223 |
5 | 4212104121440342 |
6 | 142255245201031 |
7 | 12554200031002 |
oct | 1765464743353 |
9 | 430132835581 |
10 | 136043546347 |
11 | 52772042a35 |
12 | 22448860177 |
13 | caa0ca9367 |
14 | 6827db1c39 |
15 | 38136eddb7 |
hex | 1facd3c6eb |
136043546347 has 2 divisors, whose sum is σ = 136043546348. Its totient is φ = 136043546346.
The previous prime is 136043546341. The next prime is 136043546351. The reversal of 136043546347 is 743645340631.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-136043546347 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 136043546297 and 136043546306.
It is not a weakly prime, because it can be changed into another prime (136043546341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68021773173 + 68021773174.
It is an arithmetic number, because the mean of its divisors is an integer number (68021773174).
Almost surely, 2136043546347 is an apocalyptic number.
136043546347 is a deficient number, since it is larger than the sum of its proper divisors (1).
136043546347 is an equidigital number, since it uses as much as digits as its factorization.
136043546347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2177280, while the sum is 46.
Adding to 136043546347 its reverse (743645340631), we get a palindrome (879688886978).
The spelling of 136043546347 in words is "one hundred thirty-six billion, forty-three million, five hundred forty-six thousand, three hundred forty-seven".
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