Base | Representation |
---|---|
bin | 101000100010110… |
… | …1010101110110001 |
3 | 10111210220112011121 |
4 | 1101011222232301 |
5 | 10241233041431 |
6 | 342554542241 |
7 | 45466360036 |
oct | 12105525661 |
9 | 3453815147 |
10 | 1360440241 |
11 | 638a29986 |
12 | 31b737981 |
13 | 188b0a434 |
14 | cc97538d |
15 | 7e67d611 |
hex | 5116abb1 |
1360440241 has 2 divisors, whose sum is σ = 1360440242. Its totient is φ = 1360440240.
The previous prime is 1360440163. The next prime is 1360440251. The reversal of 1360440241 is 1420440631.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 986211216 + 374229025 = 31404^2 + 19345^2 .
It is an emirp because it is prime and its reverse (1420440631) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1360440241 - 213 = 1360432049 is a prime.
It is not a weakly prime, because it can be changed into another prime (1360440251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680220120 + 680220121.
It is an arithmetic number, because the mean of its divisors is an integer number (680220121).
Almost surely, 21360440241 is an apocalyptic number.
It is an amenable number.
1360440241 is a deficient number, since it is larger than the sum of its proper divisors (1).
1360440241 is an equidigital number, since it uses as much as digits as its factorization.
1360440241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
The square root of 1360440241 is about 36884.1462013153. The cubic root of 1360440241 is about 1108.0511867228.
Adding to 1360440241 its reverse (1420440631), we get a palindrome (2780880872).
The spelling of 1360440241 in words is "one billion, three hundred sixty million, four hundred forty thousand, two hundred forty-one".
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