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136047137 is a prime number
BaseRepresentation
bin10000001101111…
…10101000100001
3100110222220120212
420012332220201
5234312002022
621255543505
73241244612
oct1006765041
9313886525
10136047137
116a882256
123968ab95
1322255085
14140d5c09
15be253e2
hex81bea21

136047137 has 2 divisors, whose sum is σ = 136047138. Its totient is φ = 136047136.

The previous prime is 136047083. The next prime is 136047157. The reversal of 136047137 is 731740631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98089216 + 37957921 = 9904^2 + 6161^2 .

It is a cyclic number.

It is not a de Polignac number, because 136047137 - 220 = 134998561 is a prime.

It is a super-3 number, since 3×1360471373 (a number of 25 digits) contains 333 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (136047157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68023568 + 68023569.

It is an arithmetic number, because the mean of its divisors is an integer number (68023569).

Almost surely, 2136047137 is an apocalyptic number.

It is an amenable number.

136047137 is a deficient number, since it is larger than the sum of its proper divisors (1).

136047137 is an equidigital number, since it uses as much as digits as its factorization.

136047137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10584, while the sum is 32.

The square root of 136047137 is about 11663.9245968070. The cubic root of 136047137 is about 514.3157242592.

Adding to 136047137 its reverse (731740631), we get a palindrome (867787768).

The spelling of 136047137 in words is "one hundred thirty-six million, forty-seven thousand, one hundred thirty-seven".