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136054041426313 is a prime number
BaseRepresentation
bin11110111011110110001100…
…110011110011100110001001
3122211201122021002000201221221
4132323312030303303212021
5120313102134101120223
61201210210324202041
740441402656600463
oct3673661463634611
9584648232021857
10136054041426313
113a39521651107a
1213314227239321
135abbac1a4c1ca
14258509d337133
1510ae127ad0b5d
hex7bbd8ccf3989

136054041426313 has 2 divisors, whose sum is σ = 136054041426314. Its totient is φ = 136054041426312.

The previous prime is 136054041426283. The next prime is 136054041426349. The reversal of 136054041426313 is 313624140450631.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 83812413727744 + 52241627698569 = 9154912^2 + 7227837^2 .

It is a cyclic number.

It is not a de Polignac number, because 136054041426313 - 29 = 136054041425801 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 136054041426313.

It is not a weakly prime, because it can be changed into another prime (136054041426913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68027020713156 + 68027020713157.

It is an arithmetic number, because the mean of its divisors is an integer number (68027020713157).

Almost surely, 2136054041426313 is an apocalyptic number.

It is an amenable number.

136054041426313 is a deficient number, since it is larger than the sum of its proper divisors (1).

136054041426313 is an equidigital number, since it uses as much as digits as its factorization.

136054041426313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 622080, while the sum is 43.

Adding to 136054041426313 its reverse (313624140450631), we get a palindrome (449678181876944).

The spelling of 136054041426313 in words is "one hundred thirty-six trillion, fifty-four billion, forty-one million, four hundred twenty-six thousand, three hundred thirteen".