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136066182050177 is a prime number
BaseRepresentation
bin11110111100000001100000…
…011100100111000110000001
3122211202210121011202022222122
4132330001200130213012001
5120313302020101101202
61201215535140014025
740442312556313361
oct3674014034470601
9584683534668878
10136066182050177
113a39a386590515
1213316655091315
135abcca807c002
1425858d18bc9a1
1510ae5d887c9a2
hex7bc060727181

136066182050177 has 2 divisors, whose sum is σ = 136066182050178. Its totient is φ = 136066182050176.

The previous prime is 136066182050081. The next prime is 136066182050231. The reversal of 136066182050177 is 771050281660631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 128200002631936 + 7866179418241 = 11322544^2 + 2804671^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-136066182050177 is a prime.

It is not a weakly prime, because it can be changed into another prime (136066182050377) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68033091025088 + 68033091025089.

It is an arithmetic number, because the mean of its divisors is an integer number (68033091025089).

Almost surely, 2136066182050177 is an apocalyptic number.

It is an amenable number.

136066182050177 is a deficient number, since it is larger than the sum of its proper divisors (1).

136066182050177 is an equidigital number, since it uses as much as digits as its factorization.

136066182050177 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2540160, while the sum is 53.

The spelling of 136066182050177 in words is "one hundred thirty-six trillion, sixty-six billion, one hundred eighty-two million, fifty thousand, one hundred seventy-seven".