Base | Representation |
---|---|
bin | 11110111100000001100000… |
… | …011100100111000110000001 |
3 | 122211202210121011202022222122 |
4 | 132330001200130213012001 |
5 | 120313302020101101202 |
6 | 1201215535140014025 |
7 | 40442312556313361 |
oct | 3674014034470601 |
9 | 584683534668878 |
10 | 136066182050177 |
11 | 3a39a386590515 |
12 | 13316655091315 |
13 | 5abcca807c002 |
14 | 25858d18bc9a1 |
15 | 10ae5d887c9a2 |
hex | 7bc060727181 |
136066182050177 has 2 divisors, whose sum is σ = 136066182050178. Its totient is φ = 136066182050176.
The previous prime is 136066182050081. The next prime is 136066182050231. The reversal of 136066182050177 is 771050281660631.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 128200002631936 + 7866179418241 = 11322544^2 + 2804671^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-136066182050177 is a prime.
It is not a weakly prime, because it can be changed into another prime (136066182050377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68033091025088 + 68033091025089.
It is an arithmetic number, because the mean of its divisors is an integer number (68033091025089).
Almost surely, 2136066182050177 is an apocalyptic number.
It is an amenable number.
136066182050177 is a deficient number, since it is larger than the sum of its proper divisors (1).
136066182050177 is an equidigital number, since it uses as much as digits as its factorization.
136066182050177 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2540160, while the sum is 53.
The spelling of 136066182050177 in words is "one hundred thirty-six trillion, sixty-six billion, one hundred eighty-two million, fifty thousand, one hundred seventy-seven".
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