136102544033537 has 2 divisors, whose sum is σ = 136102544033538. Its totient is φ = 136102544033536.

The previous prime is 136102544033483. The next prime is 136102544033581. The reversal of 136102544033537 is 735330445201631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126164136462961 + 9938407570576 = 11232281^2 + 3152524^2 .

It is a cyclic number.

It is not a de Polignac number, because 136102544033537 - 2¹⁸ = 136102543771393 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 136102544033491 and 136102544033500.

It is not a weakly prime, because it can be changed into another prime (136102544033737) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68051272016768 + 68051272016769.

It is an arithmetic number, because the mean of its divisors is an integer number (68051272016769).

Almost surely, 2^{136102544033537} is an apocalyptic number.

It is an amenable number.

136102544033537 is a deficient number, since it is larger than the sum of its proper divisors (1).

136102544033537 is an equidigital number, since it uses as much as digits as its factorization.

136102544033537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2721600, while the sum is 47.

The spelling of 136102544033537 in words is "one hundred thirty-six trillion, one hundred two billion, five hundred forty-four million, thirty-three thousand, five hundred thirty-seven".