1361202310034 has 8 divisors (see below), whose sum is σ = 2333489674368. Its totient is φ = 583372418580.

The previous prime is 1361202310033. The next prime is 1361202310049. The reversal of 1361202310034 is 4300132021631.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×1361202310034³ (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1361202309985 and 1361202310012.

It is not an unprimeable number, because it can be changed into a prime (1361202310033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48614368202 + ... + 48614368229.

It is an arithmetic number, because the mean of its divisors is an integer number (291686209296).

Almost surely, 2^{1361202310034} is an apocalyptic number.

1361202310034 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

1361202310034 is a deficient number, since it is larger than the sum of its proper divisors (972287364334).

1361202310034 is an equidigital number, since it uses as much as digits as its factorization.

1361202310034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 97228736440.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 1361202310034 its reverse (4300132021631), we get a palindrome (5661334331665).

The spelling of 1361202310034 in words is "one trillion, three hundred sixty-one billion, two hundred two million, three hundred ten thousand, thirty-four".