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1361205623497 is a prime number
BaseRepresentation
bin10011110011101110001…
…011010111101011001001
311211010111202112021111111
4103303232023113223021
5134300222114422442
62521155040330321
7200225641615366
oct23635613275311
94733452467444
101361205623497
114853140a7005
1219b9890139a1
139b4905675c5
1449c501d346d
152561c424b17
hex13cee2d7ac9

1361205623497 has 2 divisors, whose sum is σ = 1361205623498. Its totient is φ = 1361205623496.

The previous prime is 1361205623467. The next prime is 1361205623543. The reversal of 1361205623497 is 7943265021631.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1200648339081 + 160557284416 = 1095741^2 + 400696^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1361205623497 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1361205623497.

It is not a weakly prime, because it can be changed into another prime (1361205623467) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680602811748 + 680602811749.

It is an arithmetic number, because the mean of its divisors is an integer number (680602811749).

Almost surely, 21361205623497 is an apocalyptic number.

It is an amenable number.

1361205623497 is a deficient number, since it is larger than the sum of its proper divisors (1).

1361205623497 is an equidigital number, since it uses as much as digits as its factorization.

1361205623497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1632960, while the sum is 49.

The spelling of 1361205623497 in words is "one trillion, three hundred sixty-one billion, two hundred five million, six hundred twenty-three thousand, four hundred ninety-seven".