Base | Representation |
---|---|
bin | 10011110011101110001… |
… | …011010111101011001001 |
3 | 11211010111202112021111111 |
4 | 103303232023113223021 |
5 | 134300222114422442 |
6 | 2521155040330321 |
7 | 200225641615366 |
oct | 23635613275311 |
9 | 4733452467444 |
10 | 1361205623497 |
11 | 4853140a7005 |
12 | 19b9890139a1 |
13 | 9b4905675c5 |
14 | 49c501d346d |
15 | 2561c424b17 |
hex | 13cee2d7ac9 |
1361205623497 has 2 divisors, whose sum is σ = 1361205623498. Its totient is φ = 1361205623496.
The previous prime is 1361205623467. The next prime is 1361205623543. The reversal of 1361205623497 is 7943265021631.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1200648339081 + 160557284416 = 1095741^2 + 400696^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1361205623497 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1361205623497.
It is not a weakly prime, because it can be changed into another prime (1361205623467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680602811748 + 680602811749.
It is an arithmetic number, because the mean of its divisors is an integer number (680602811749).
Almost surely, 21361205623497 is an apocalyptic number.
It is an amenable number.
1361205623497 is a deficient number, since it is larger than the sum of its proper divisors (1).
1361205623497 is an equidigital number, since it uses as much as digits as its factorization.
1361205623497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1632960, while the sum is 49.
The spelling of 1361205623497 in words is "one trillion, three hundred sixty-one billion, two hundred five million, six hundred twenty-three thousand, four hundred ninety-seven".
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