Base | Representation |
---|---|
bin | 10011110011101110001… |
… | …101000010101010001011 |
3 | 11211010111210100112121111 |
4 | 103303232031002222023 |
5 | 134300222222433312 |
6 | 2521155053551151 |
7 | 200225645422102 |
oct | 23635615025213 |
9 | 4733453315544 |
10 | 1361206061707 |
11 | 485314376268 |
12 | 19b9891a54b7 |
13 | 9b49068bbbb |
14 | 49c502a9039 |
15 | 2561c4ae8a7 |
hex | 13cee342a8b |
1361206061707 has 2 divisors, whose sum is σ = 1361206061708. Its totient is φ = 1361206061706.
The previous prime is 1361206061693. The next prime is 1361206061713. The reversal of 1361206061707 is 7071606021631.
It is a strong prime.
It is an emirp because it is prime and its reverse (7071606021631) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1361206061707 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1361206061707.
It is not a weakly prime, because it can be changed into another prime (1361206061507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680603030853 + 680603030854.
It is an arithmetic number, because the mean of its divisors is an integer number (680603030854).
Almost surely, 21361206061707 is an apocalyptic number.
1361206061707 is a deficient number, since it is larger than the sum of its proper divisors (1).
1361206061707 is an equidigital number, since it uses as much as digits as its factorization.
1361206061707 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 63504, while the sum is 40.
The spelling of 1361206061707 in words is "one trillion, three hundred sixty-one billion, two hundred six million, sixty-one thousand, seven hundred seven".
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