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1361250073641 = 3453750024547
BaseRepresentation
bin10011110011110000110…
…100111011110000101001
311211010121212011120122010
4103303300310323300221
5134300320004324031
62521203305150133
7200230021466553
oct23636064736051
94733555146563
101361250073641
114853371a7067
1219b99ba8b349
139b49982b873
1449c560844d3
15256212a5246
hex13cf0d3bc29

1361250073641 has 4 divisors (see below), whose sum is σ = 1815000098192. Its totient is φ = 907500049092.

The previous prime is 1361250073637. The next prime is 1361250073643. The reversal of 1361250073641 is 1463700521631.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1361250073641 - 22 = 1361250073637 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1361250073641.

It is not an unprimeable number, because it can be changed into a prime (1361250073643) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 226875012271 + ... + 226875012276.

It is an arithmetic number, because the mean of its divisors is an integer number (453750024548).

Almost surely, 21361250073641 is an apocalyptic number.

It is an amenable number.

1361250073641 is a deficient number, since it is larger than the sum of its proper divisors (453750024551).

1361250073641 is an equidigital number, since it uses as much as digits as its factorization.

1361250073641 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 453750024550.

The product of its (nonzero) digits is 90720, while the sum is 39.

The spelling of 1361250073641 in words is "one trillion, three hundred sixty-one billion, two hundred fifty million, seventy-three thousand, six hundred forty-one".

Divisors: 1 3 453750024547 1361250073641