1361260365041 has 4 divisors (see below), whose sum is σ = 1361274841584. Its totient is φ = 1361245888500.

The previous prime is 1361260365037. The next prime is 1361260365071. The reversal of 1361260365041 is 1405630621631.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1361260365041 - 2² = 1361260365037 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1361260364986 and 1361260365004.

It is not an unprimeable number, because it can be changed into a prime (1361260365071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7096295 + ... + 7285596.

It is an arithmetic number, because the mean of its divisors is an integer number (340318710396).

Almost surely, 2^{1361260365041} is an apocalyptic number.

It is an amenable number.

1361260365041 is a deficient number, since it is larger than the sum of its proper divisors (14476543).

1361260365041 is an equidigital number, since it uses as much as digits as its factorization.

1361260365041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14476542.

The product of its (nonzero) digits is 77760, while the sum is 38.

Adding to 1361260365041 its reverse (1405630621631), we get a palindrome (2766890986672).

The spelling of 1361260365041 in words is "one trillion, three hundred sixty-one billion, two hundred sixty million, three hundred sixty-five thousand, forty-one".