Base | Representation |
---|---|
bin | 10011110011110110110… |
… | …110000110100101101011 |
3 | 11211010212220011101011010 |
4 | 103303312312012211223 |
5 | 134301021331342220 |
6 | 2521221313235003 |
7 | 200232355641255 |
oct | 23636666064553 |
9 | 4733786141133 |
10 | 1361351043435 |
11 | 4853891a0179 |
12 | 19ba09862a63 |
13 | 9b4b47218c6 |
14 | 49c65648cd5 |
15 | 2562a09c1e0 |
hex | 13cf6d8696b |
1361351043435 has 32 divisors (see below), whose sum is σ = 2193375578688. Its totient is φ = 721000232960.
The previous prime is 1361351043433. The next prime is 1361351043443. The reversal of 1361351043435 is 5343401531631.
It is not a de Polignac number, because 1361351043435 - 21 = 1361351043433 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1361351043393 and 1361351043402.
It is not an unprimeable number, because it can be changed into a prime (1361351043433) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 683839 + ... + 1786151.
It is an arithmetic number, because the mean of its divisors is an integer number (68542986834).
Almost surely, 21361351043435 is an apocalyptic number.
1361351043435 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1361351043435 is a deficient number, since it is larger than the sum of its proper divisors (832024535253).
1361351043435 is a wasteful number, since it uses less digits than its factorization.
1361351043435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1102895.
The product of its (nonzero) digits is 194400, while the sum is 39.
The spelling of 1361351043435 in words is "one trillion, three hundred sixty-one billion, three hundred fifty-one million, forty-three thousand, four hundred thirty-five".
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