Base | Representation |
---|---|
bin | 10011110011110111101… |
… | …110010000100000110011 |
3 | 11211010220220212021011200 |
4 | 103303313232100200303 |
5 | 134301034113423042 |
6 | 2521223000542243 |
7 | 200232625031634 |
oct | 23636756204063 |
9 | 4733826767150 |
10 | 1361365764147 |
11 | 485396535054 |
12 | 19ba12781983 |
13 | 9b4b77a709c |
14 | 49c6759b88b |
15 | 2562b508c4c |
hex | 13cf7b90833 |
1361365764147 has 6 divisors (see below), whose sum is σ = 1966417214892. Its totient is φ = 907577176092.
The previous prime is 1361365764049. The next prime is 1361365764179. The reversal of 1361365764147 is 7414675631631.
1361365764147 is a `hidden beast` number, since 1 + 3 + 61 + 3 + 6 + 576 + 4 + 1 + 4 + 7 = 666.
It is not a de Polignac number, because 1361365764147 - 27 = 1361365764019 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1361365764093 and 1361365764102.
It is not an unprimeable number, because it can be changed into a prime (1361365764047) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 75631431333 + ... + 75631431350.
It is an arithmetic number, because the mean of its divisors is an integer number (327736202482).
Almost surely, 21361365764147 is an apocalyptic number.
1361365764147 is a deficient number, since it is larger than the sum of its proper divisors (605051450745).
1361365764147 is a wasteful number, since it uses less digits than its factorization.
1361365764147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 151262862689 (or 151262862686 counting only the distinct ones).
The product of its digits is 7620480, while the sum is 54.
The spelling of 1361365764147 in words is "one trillion, three hundred sixty-one billion, three hundred sixty-five million, seven hundred sixty-four thousand, one hundred forty-seven".
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