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1361374406753 is a prime number
BaseRepresentation
bin10011110011111000001…
…111001110100001100001
311211010221112010100121012
4103303320033032201201
5134301043322004003
62521223510110305
7200233061346014
oct23637017164141
94733845110535
101361374406753
114853a03a83a9
1219ba1564b395
139b4b9511b5a
1449c687ab37b
152562c1648d8
hex13cf83ce861

1361374406753 has 2 divisors, whose sum is σ = 1361374406754. Its totient is φ = 1361374406752.

The previous prime is 1361374406617. The next prime is 1361374406767. The reversal of 1361374406753 is 3576044731631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1235670122449 + 125704284304 = 1111607^2 + 354548^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1361374406753 is a prime.

It is not a weakly prime, because it can be changed into another prime (1361374406783) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680687203376 + 680687203377.

It is an arithmetic number, because the mean of its divisors is an integer number (680687203377).

Almost surely, 21361374406753 is an apocalyptic number.

It is an amenable number.

1361374406753 is a deficient number, since it is larger than the sum of its proper divisors (1).

1361374406753 is an equidigital number, since it uses as much as digits as its factorization.

1361374406753 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3810240, while the sum is 50.

The spelling of 1361374406753 in words is "one trillion, three hundred sixty-one billion, three hundred seventy-four million, four hundred six thousand, seven hundred fifty-three".