Base | Representation |
---|---|
bin | 111111011001010100… |
… | …0000010011111101011 |
3 | 111000101212222120002011 |
4 | 1332302220002133223 |
5 | 4212304022422403 |
6 | 142313042220351 |
7 | 12556460634625 |
oct | 1766250023753 |
9 | 430355876064 |
10 | 136140826603 |
11 | 52811a47041 |
12 | 224753546b7 |
13 | cab81a9c42 |
14 | 6836c95c15 |
15 | 381c017a6d |
hex | 1fb2a027eb |
136140826603 has 4 divisors (see below), whose sum is σ = 136892986048. Its totient is φ = 135388667160.
The previous prime is 136140826571. The next prime is 136140826631. The reversal of 136140826603 is 306628041631.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 306628041631 = 102763 ⋅2983837.
It is a cyclic number.
It is not a de Polignac number, because 136140826603 - 25 = 136140826571 is a prime.
It is a super-2 number, since 2×1361408266032 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (136140826693) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 376079451 + ... + 376079812.
It is an arithmetic number, because the mean of its divisors is an integer number (34223246512).
Almost surely, 2136140826603 is an apocalyptic number.
136140826603 is a deficient number, since it is larger than the sum of its proper divisors (752159445).
136140826603 is an equidigital number, since it uses as much as digits as its factorization.
136140826603 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 752159444.
The product of its (nonzero) digits is 124416, while the sum is 40.
The spelling of 136140826603 in words is "one hundred thirty-six billion, one hundred forty million, eight hundred twenty-six thousand, six hundred three".
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