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136151325641 is a prime number
BaseRepresentation
bin111111011001101000…
…0000101101111001001
3111000102121201222001102
41332303100011233021
54212314214410031
6142314055231145
712556646113232
oct1766320055711
9430377658042
10136151325641
1152817968131
12224789784b5
13caba4149a6
14683842a089
15381cddd7cb
hex1fb3405bc9

136151325641 has 2 divisors, whose sum is σ = 136151325642. Its totient is φ = 136151325640.

The previous prime is 136151325577. The next prime is 136151325647. The reversal of 136151325641 is 146523151631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 122531502025 + 13619823616 = 350045^2 + 116704^2 .

It is a cyclic number.

It is not a de Polignac number, because 136151325641 - 26 = 136151325577 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 136151325595 and 136151325604.

It is not a weakly prime, because it can be changed into another prime (136151325647) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68075662820 + 68075662821.

It is an arithmetic number, because the mean of its divisors is an integer number (68075662821).

Almost surely, 2136151325641 is an apocalyptic number.

It is an amenable number.

136151325641 is a deficient number, since it is larger than the sum of its proper divisors (1).

136151325641 is an equidigital number, since it uses as much as digits as its factorization.

136151325641 is an evil number, because the sum of its binary digits is even.

The product of its digits is 64800, while the sum is 38.

The spelling of 136151325641 in words is "one hundred thirty-six billion, one hundred fifty-one million, three hundred twenty-five thousand, six hundred forty-one".