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1361725006569 = 3453908335523
BaseRepresentation
bin10011110100001101001…
…000101010001011101001
311211011211221211200010120
4103310031020222023221
5134302303100202234
62521322352433453
7200244546401634
oct23641510521351
94734757750116
101361725006569
114855602a2214
1219bab2b48889
139b544048075
1449c9d192c1b
152564cd1b049
hex13d0d22a2e9

1361725006569 has 4 divisors (see below), whose sum is σ = 1815633342096. Its totient is φ = 907816671044.

The previous prime is 1361725006567. The next prime is 1361725006573. The reversal of 1361725006569 is 9656005271631.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1361725006569 - 21 = 1361725006567 is a prime.

It is a super-2 number, since 2×13617250065692 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1361725006567) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 226954167759 + ... + 226954167764.

It is an arithmetic number, because the mean of its divisors is an integer number (453908335524).

Almost surely, 21361725006569 is an apocalyptic number.

It is an amenable number.

1361725006569 is a deficient number, since it is larger than the sum of its proper divisors (453908335527).

1361725006569 is an equidigital number, since it uses as much as digits as its factorization.

1361725006569 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 453908335526.

The product of its (nonzero) digits is 2041200, while the sum is 51.

The spelling of 1361725006569 in words is "one trillion, three hundred sixty-one billion, seven hundred twenty-five million, six thousand, five hundred sixty-nine".

Divisors: 1 3 453908335523 1361725006569