Base | Representation |
---|---|
bin | 111111011010100011… |
… | …1100110010001011001 |
3 | 111000111210200121112112 |
4 | 1332311013212101121 |
5 | 4212400224412131 |
6 | 142321134522105 |
7 | 12560506313540 |
oct | 1766507462131 |
9 | 430453617475 |
10 | 136182654041 |
11 | 52833615675 |
12 | 22487366335 |
13 | cac3a634c5 |
14 | 683c663157 |
15 | 3820a2b02b |
hex | 1fb51e6459 |
136182654041 has 4 divisors (see below), whose sum is σ = 155637318912. Its totient is φ = 116727989172.
The previous prime is 136182654007. The next prime is 136182654053. The reversal of 136182654041 is 140456281631.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-136182654041 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 136182654041.
It is not an unprimeable number, because it can be changed into a prime (136182654061) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9727332425 + ... + 9727332438.
It is an arithmetic number, because the mean of its divisors is an integer number (38909329728).
Almost surely, 2136182654041 is an apocalyptic number.
It is an amenable number.
136182654041 is a deficient number, since it is larger than the sum of its proper divisors (19454664871).
136182654041 is an equidigital number, since it uses as much as digits as its factorization.
136182654041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19454664870.
The product of its (nonzero) digits is 138240, while the sum is 41.
The spelling of 136182654041 in words is "one hundred thirty-six billion, one hundred eighty-two million, six hundred fifty-four thousand, forty-one".
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