1362017402041 has 2 divisors, whose sum is σ = 1362017402042. Its totient is φ = 1362017402040.

The previous prime is 1362017402033. The next prime is 1362017402107. The reversal of 1362017402041 is 1402047102631.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1342910145600 + 19107256441 = 1158840^2 + 138229^2 .

It is a cyclic number.

It is not a de Polignac number, because 1362017402041 - 2³ = 1362017402033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1362017401994 and 1362017402012.

It is not a weakly prime, because it can be changed into another prime (1362017402021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 681008701020 + 681008701021.

It is an arithmetic number, because the mean of its divisors is an integer number (681008701021).

Almost surely, 2^{1362017402041} is an apocalyptic number.

It is an amenable number.

1362017402041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1362017402041 is an equidigital number, since it uses as much as digits as its factorization.

1362017402041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8064, while the sum is 31.

The spelling of 1362017402041 in words is "one trillion, three hundred sixty-two billion, seventeen million, four hundred two thousand, forty-one".