Base | Representation |
---|---|
bin | 111111011011001011… |
… | …1010111011001100011 |
3 | 111000120021000222111021 |
4 | 1332312113113121203 |
5 | 4212421103032033 |
6 | 142323203030311 |
7 | 12561152124436 |
oct | 1766627273143 |
9 | 430507028437 |
10 | 136203564643 |
11 | 528443a8063 |
12 | 2249236b397 |
13 | cac81a5243 |
14 | 684134781d |
15 | 38227abb2d |
hex | 1fb65d7663 |
136203564643 has 2 divisors, whose sum is σ = 136203564644. Its totient is φ = 136203564642.
The previous prime is 136203564619. The next prime is 136203564661. The reversal of 136203564643 is 346465302631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 136203564643 - 225 = 136170010211 is a prime.
It is a super-2 number, since 2×1362035646432 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 136203564643.
It is not a weakly prime, because it can be changed into another prime (136203565643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68101782321 + 68101782322.
It is an arithmetic number, because the mean of its divisors is an integer number (68101782322).
Almost surely, 2136203564643 is an apocalyptic number.
136203564643 is a deficient number, since it is larger than the sum of its proper divisors (1).
136203564643 is an equidigital number, since it uses as much as digits as its factorization.
136203564643 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 933120, while the sum is 43.
The spelling of 136203564643 in words is "one hundred thirty-six billion, two hundred three million, five hundred sixty-four thousand, six hundred forty-three".
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