Base | Representation |
---|---|
bin | 10011110100100100100… |
… | …001011001000000001011 |
3 | 11211012212022010120202212 |
4 | 103310210201121000023 |
5 | 134304104021201041 |
6 | 2521425330215335 |
7 | 200260352401211 |
oct | 23644441310013 |
9 | 4735768116685 |
10 | 1362117365771 |
11 | 485741819518 |
12 | 19bba242454b |
13 | 9b5a7412886 |
14 | 49cd9328cb1 |
15 | 256724c08eb |
hex | 13d2485900b |
1362117365771 has 2 divisors, whose sum is σ = 1362117365772. Its totient is φ = 1362117365770.
The previous prime is 1362117365723. The next prime is 1362117365789. The reversal of 1362117365771 is 1775637112631.
It is a strong prime.
It is an emirp because it is prime and its reverse (1775637112631) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1362117365771 is a prime.
It is not a weakly prime, because it can be changed into another prime (1362117365671) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 681058682885 + 681058682886.
It is an arithmetic number, because the mean of its divisors is an integer number (681058682886).
Almost surely, 21362117365771 is an apocalyptic number.
1362117365771 is a deficient number, since it is larger than the sum of its proper divisors (1).
1362117365771 is an equidigital number, since it uses as much as digits as its factorization.
1362117365771 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1111320, while the sum is 50.
The spelling of 1362117365771 in words is "one trillion, three hundred sixty-two billion, one hundred seventeen million, three hundred sixty-five thousand, seven hundred seventy-one".
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