Base | Representation |
---|---|
bin | 10011110100100100110… |
… | …111101111111110101011 |
3 | 11211012212201011100221022 |
4 | 103310210313233332223 |
5 | 134304112021231201 |
6 | 2521430100003055 |
7 | 200260453252406 |
oct | 23644467577653 |
9 | 4735781140838 |
10 | 1362123227051 |
11 | 485745062154 |
12 | 19bba439048b |
13 | 9b5a86b56a2 |
14 | 49cda012d3d |
15 | 25672c7c41b |
hex | 13d24deffab |
1362123227051 has 2 divisors, whose sum is σ = 1362123227052. Its totient is φ = 1362123227050.
The previous prime is 1362123227009. The next prime is 1362123227057. The reversal of 1362123227051 is 1507223212631.
It is a strong prime.
It is an emirp because it is prime and its reverse (1507223212631) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1362123227051 - 210 = 1362123226027 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (1362123227057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 681061613525 + 681061613526.
It is an arithmetic number, because the mean of its divisors is an integer number (681061613526).
Almost surely, 21362123227051 is an apocalyptic number.
1362123227051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1362123227051 is an equidigital number, since it uses as much as digits as its factorization.
1362123227051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 30240, while the sum is 35.
Adding to 1362123227051 its reverse (1507223212631), we get a palindrome (2869346439682).
The spelling of 1362123227051 in words is "one trillion, three hundred sixty-two billion, one hundred twenty-three million, two hundred twenty-seven thousand, fifty-one".
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