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13621362513433 is a prime number
BaseRepresentation
bin1100011000110111100001…
…1110010101011000011001
31210020012010011200201001221
43012031320132111120121
53241133022300412213
644545322331412041
72604053026666603
oct306157036253031
953205104621057
1013621362513433
114381873037874
12163bab28b4021
1377a6483754cc
143513c5506173
151894c9bad38d
hexc6378795619

13621362513433 has 2 divisors, whose sum is σ = 13621362513434. Its totient is φ = 13621362513432.

The previous prime is 13621362513427. The next prime is 13621362513449. The reversal of 13621362513433 is 33431526312631.

13621362513433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11667327568009 + 1954034945424 = 3415747^2 + 1397868^2 .

It is a cyclic number.

It is not a de Polignac number, because 13621362513433 - 213 = 13621362505241 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13621362513433.

It is not a weakly prime, because it can be changed into another prime (13621362513403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6810681256716 + 6810681256717.

It is an arithmetic number, because the mean of its divisors is an integer number (6810681256717).

Almost surely, 213621362513433 is an apocalyptic number.

It is an amenable number.

13621362513433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13621362513433 is an equidigital number, since it uses as much as digits as its factorization.

13621362513433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 699840, while the sum is 43.

The spelling of 13621362513433 in words is "thirteen trillion, six hundred twenty-one billion, three hundred sixty-two million, five hundred thirteen thousand, four hundred thirty-three".