13625113110001 has 2 divisors, whose sum is σ = 13625113110002. Its totient is φ = 13625113110000.

The previous prime is 13625113109969. The next prime is 13625113110041. The reversal of 13625113110001 is 10001131152631.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8932686337600 + 4692426772401 = 2988760^2 + 2166201^2 .

It is a cyclic number.

It is not a de Polignac number, because 13625113110001 - 2⁵ = 13625113109969 is a prime.

It is a super-2 number, since 2×13625113110001² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13625113110041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6812556555000 + 6812556555001.

It is an arithmetic number, because the mean of its divisors is an integer number (6812556555001).

Almost surely, 2^{13625113110001} is an apocalyptic number.

It is an amenable number.

13625113110001 is a deficient number, since it is larger than the sum of its proper divisors (1).

13625113110001 is an equidigital number, since it uses as much as digits as its factorization.

13625113110001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 25.

Adding to 13625113110001 its reverse (10001131152631), we get a palindrome (23626244262632).

The spelling of 13625113110001 in words is "thirteen trillion, six hundred twenty-five billion, one hundred thirteen million, one hundred ten thousand, one".