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13631004223657 is a prime number
BaseRepresentation
bin1100011001011011011100…
…1010100010100010101001
31210021010000010021100000121
43012112313022202202221
53241312244040124112
644553555155003241
72604543664120132
oct306266712424251
953233003240017
1013631004223657
114385970585427
121641943899521
1377b523a664a2
14351a5bc40c89
15189891396407
hexc65b72a28a9

13631004223657 has 2 divisors, whose sum is σ = 13631004223658. Its totient is φ = 13631004223656.

The previous prime is 13631004223631. The next prime is 13631004223663. The reversal of 13631004223657 is 75632240013631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12901968308761 + 729035914896 = 3591931^2 + 853836^2 .

It is a cyclic number.

It is not a de Polignac number, because 13631004223657 - 239 = 13081248409769 is a prime.

It is a super-2 number, since 2×136310042236572 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13631004223457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6815502111828 + 6815502111829.

It is an arithmetic number, because the mean of its divisors is an integer number (6815502111829).

Almost surely, 213631004223657 is an apocalyptic number.

It is an amenable number.

13631004223657 is a deficient number, since it is larger than the sum of its proper divisors (1).

13631004223657 is an equidigital number, since it uses as much as digits as its factorization.

13631004223657 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 544320, while the sum is 43.

The spelling of 13631004223657 in words is "thirteen trillion, six hundred thirty-one billion, four million, two hundred twenty-three thousand, six hundred fifty-seven".