Base | Representation |
---|---|
bin | 11110111111110011001110… |
… | …001111010111110100010010 |
3 | 122212200121111222011111122012 |
4 | 132333303032033113310102 |
5 | 120332030034330030000 |
6 | 1201535101104142522 |
7 | 40500131323402310 |
oct | 3677631617276422 |
9 | 585617458144565 |
10 | 136325722111250 |
11 | 3a48a461144861 |
12 | 13358a08607a42 |
13 | 5b0b5ca75b849 |
14 | 25942b33290b0 |
15 | 10b6228ea1735 |
hex | 7bfcce3d7d12 |
136325722111250 has 80 divisors (see below), whose sum is σ = 292107809879424. Its totient is φ = 46728284880000.
The previous prime is 136325722111231. The next prime is 136325722111273. The reversal of 136325722111250 is 52111227523631.
It is a junction number, because it is equal to n+sod(n) for n = 136325722111198 and 136325722111207.
It is an unprimeable number.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 32229422 + ... + 36213078.
Almost surely, 2136325722111250 is an apocalyptic number.
136325722111250 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
136325722111250 is an abundant number, since it is smaller than the sum of its proper divisors (155782087768174).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
136325722111250 is an equidigital number, since it uses as much as digits as its factorization.
136325722111250 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3987597 (or 3987582 counting only the distinct ones).
The product of its (nonzero) digits is 151200, while the sum is 41.
Adding to 136325722111250 its reverse (52111227523631), we get a palindrome (188436949634881).
The spelling of 136325722111250 in words is "one hundred thirty-six trillion, three hundred twenty-five billion, seven hundred twenty-two million, one hundred eleven thousand, two hundred fifty".
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