1363407314161 has 4 divisors (see below), whose sum is σ = 1372436501824. Its totient is φ = 1354378126500.

The previous prime is 1363407314153. The next prime is 1363407314177. The reversal of 1363407314161 is 1614137043631.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1363407314161 - 2³ = 1363407314153 is a prime.

It is a super-2 number, since 2×1363407314161² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1363407314461) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4514593605 + ... + 4514593906.

It is an arithmetic number, because the mean of its divisors is an integer number (343109125456).

Almost surely, 2^{1363407314161} is an apocalyptic number.

It is an amenable number.

1363407314161 is a deficient number, since it is larger than the sum of its proper divisors (9029187663).

1363407314161 is an equidigital number, since it uses as much as digits as its factorization.

1363407314161 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9029187662.

The product of its (nonzero) digits is 108864, while the sum is 40.

The spelling of 1363407314161 in words is "one trillion, three hundred sixty-three billion, four hundred seven million, three hundred fourteen thousand, one hundred sixty-one".