Base | Representation |
---|---|
bin | 111111011111011000… |
… | …0110001101100001001 |
3 | 111000221002010101011112 |
4 | 1332332300301230021 |
5 | 4213213134144112 |
6 | 142345154340105 |
7 | 12564512435432 |
oct | 1767660615411 |
9 | 430832111145 |
10 | 136344443657 |
11 | 5290697a5a4 |
12 | 2251158a635 |
13 | cb1b42c6c6 |
14 | 6855d3a489 |
15 | 382ed38a22 |
hex | 1fbec31b09 |
136344443657 has 2 divisors, whose sum is σ = 136344443658. Its totient is φ = 136344443656.
The previous prime is 136344443633. The next prime is 136344443671. The reversal of 136344443657 is 756344443631.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 133772331001 + 2572112656 = 365749^2 + 50716^2 .
It is a cyclic number.
It is not a de Polignac number, because 136344443657 - 28 = 136344443401 is a prime.
It is a super-2 number, since 2×1363444436572 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (136344443857) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68172221828 + 68172221829.
It is an arithmetic number, because the mean of its divisors is an integer number (68172221829).
Almost surely, 2136344443657 is an apocalyptic number.
It is an amenable number.
136344443657 is a deficient number, since it is larger than the sum of its proper divisors (1).
136344443657 is an equidigital number, since it uses as much as digits as its factorization.
136344443657 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 8709120, while the sum is 50.
The spelling of 136344443657 in words is "one hundred thirty-six billion, three hundred forty-four million, four hundred forty-three thousand, six hundred fifty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •