Base | Representation |
---|---|
bin | 111111100001011001… |
… | …1010101111010001001 |
3 | 111001002210200000220121 |
4 | 1333002303111322021 |
5 | 4213333012201121 |
6 | 142400015223241 |
7 | 12566264532232 |
oct | 1770263257211 |
9 | 431083600817 |
10 | 136412225161 |
11 | 52941165873 |
12 | 22530217b21 |
13 | cb2c4a24c4 |
14 | 6860d42089 |
15 | 3835c77141 |
hex | 1fc2cd5e89 |
136412225161 has 2 divisors, whose sum is σ = 136412225162. Its totient is φ = 136412225160.
The previous prime is 136412225119. The next prime is 136412225177. The reversal of 136412225161 is 161522214631.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 89353166400 + 47059058761 = 298920^2 + 216931^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-136412225161 is a prime.
It is a super-2 number, since 2×1364122251612 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (136412225101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68206112580 + 68206112581.
It is an arithmetic number, because the mean of its divisors is an integer number (68206112581).
Almost surely, 2136412225161 is an apocalyptic number.
It is an amenable number.
136412225161 is a deficient number, since it is larger than the sum of its proper divisors (1).
136412225161 is an equidigital number, since it uses as much as digits as its factorization.
136412225161 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 17280, while the sum is 34.
Adding to 136412225161 its reverse (161522214631), we get a palindrome (297934439792).
The spelling of 136412225161 in words is "one hundred thirty-six billion, four hundred twelve million, two hundred twenty-five thousand, one hundred sixty-one".
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