13642320104403 has 4 divisors (see below), whose sum is σ = 18189760139208. Its totient is φ = 9094880069600.

The previous prime is 13642320104341. The next prime is 13642320104437. The reversal of 13642320104403 is 30440102324631.

13642320104403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13642320104403 - 2¹² = 13642320100307 is a prime.

It is a super-2 number, since 2×13642320104403² (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13642320104473) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2273720017398 + ... + 2273720017403.

It is an arithmetic number, because the mean of its divisors is an integer number (4547440034802).

Almost surely, 2^{13642320104403} is an apocalyptic number.

13642320104403 is a deficient number, since it is larger than the sum of its proper divisors (4547440034805).

13642320104403 is an equidigital number, since it uses as much as digits as its factorization.

13642320104403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4547440034804.

The product of its (nonzero) digits is 41472, while the sum is 33.

The spelling of 13642320104403 in words is "thirteen trillion, six hundred forty-two billion, three hundred twenty million, one hundred four thousand, four hundred three".