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13642524971 = 121711209963
BaseRepresentation
bin11001011010010100…
…00110100100101011
31022012202211002000122
430231022012210223
5210414441244341
610133422353455
7662034356165
oct145512064453
938182732018
1013642524971
115870938a29
122788a2b88b
1313955394aa
14935c21935
1554ca6e94b
hex32d28692b

13642524971 has 4 divisors (see below), whose sum is σ = 13653736152. Its totient is φ = 13631313792.

The previous prime is 13642524953. The next prime is 13642525021. The reversal of 13642524971 is 17942524631.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 17942524631 = 20431878201.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13642524971 is a prime.

It is a super-2 number, since 2×136425249712 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13642524941) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5603765 + ... + 5606198.

It is an arithmetic number, because the mean of its divisors is an integer number (3413434038).

Almost surely, 213642524971 is an apocalyptic number.

13642524971 is a deficient number, since it is larger than the sum of its proper divisors (11211181).

13642524971 is a wasteful number, since it uses less digits than its factorization.

13642524971 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11211180.

The product of its digits is 362880, while the sum is 44.

The spelling of 13642524971 in words is "thirteen billion, six hundred forty-two million, five hundred twenty-four thousand, nine hundred seventy-one".

Divisors: 1 1217 11209963 13642524971