1365113147 has 2 divisors, whose sum is σ = 1365113148. Its totient is φ = 1365113146.

The previous prime is 1365113093. The next prime is 1365113153. The reversal of 1365113147 is 7413115631.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1365113147 - 2¹⁶ = 1365047611 is a prime.

It is a super-2 number, since 2×1365113147² = 3727067808224487218, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1365113177) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 682556573 + 682556574.

It is an arithmetic number, because the mean of its divisors is an integer number (682556574).

Almost surely, 2^1365113147 is an apocalyptic number.

1365113147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1365113147 is an equidigital number, since it uses as much as digits as its factorization.

1365113147 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7560, while the sum is 32.

The square root of 1365113147 is about 36947.4376242792. The cubic root of 1365113147 is about 1109.3183995531.

Adding to 1365113147 its reverse (7413115631), we get a palindrome (8778228778).

The spelling of 1365113147 in words is "one billion, three hundred sixty-five million, one hundred thirteen thousand, one hundred forty-seven".