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136511325451 = 1131208064827
BaseRepresentation
bin111111100100010110…
…1011000010100001011
3111001100201010211221201
41333020231120110023
54214033344403301
6142413515245031
712601610056324
oct1771055302413
9431321124851
10136511325451
11529920a2336
1222559449777
13cb46b8c627
14687017b44b
15383e800201
hex1fc8b5850b

136511325451 has 4 divisors (see below), whose sum is σ = 137719390392. Its totient is φ = 135303260512.

The previous prime is 136511325449. The next prime is 136511325499. The reversal of 136511325451 is 154523115631.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 154523115631 = 690672237293.

It is a cyclic number.

It is not a de Polignac number, because 136511325451 - 21 = 136511325449 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 136511325451.

It is not an unprimeable number, because it can be changed into a prime (136511725451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 604032301 + ... + 604032526.

It is an arithmetic number, because the mean of its divisors is an integer number (34429847598).

Almost surely, 2136511325451 is an apocalyptic number.

136511325451 is a deficient number, since it is larger than the sum of its proper divisors (1208064941).

136511325451 is a wasteful number, since it uses less digits than its factorization.

136511325451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1208064940.

The product of its digits is 54000, while the sum is 37.

The spelling of 136511325451 in words is "one hundred thirty-six billion, five hundred eleven million, three hundred twenty-five thousand, four hundred fifty-one".

Divisors: 1 113 1208064827 136511325451