Base | Representation |
---|---|
bin | 11111000010111111011101… |
… | …011110010100110010000001 |
3 | 122220110120120021202101210101 |
4 | 133002333131132110302001 |
5 | 120344123200340140223 |
6 | 1202223530001002401 |
7 | 40522023624362242 |
oct | 3702773536246201 |
9 | 586416507671711 |
10 | 136545021021313 |
11 | 3a564466710803 |
12 | 1339340b323401 |
13 | 5b261a9124118 |
14 | 25a0b58552cc9 |
15 | 10bbcb18564ad |
hex | 7c2fdd794c81 |
136545021021313 has 4 divisors (see below), whose sum is σ = 140235426994900. Its totient is φ = 132854615047728.
The previous prime is 136545021021187. The next prime is 136545021021329. The reversal of 136545021021313 is 313120120545631.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 122179154827024 + 14365866194289 = 11053468^2 + 3790233^2 .
It is a cyclic number.
It is not a de Polignac number, because 136545021021313 - 241 = 134345997765761 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (37), and also a Moran number because the ratio is a prime number: 3690405973549 = 136545021021313 / (1 + 3 + 6 + 5 + 4 + 5 + 0 + 2 + 1 + 0 + 2 + 1 + 3 + 1 + 3).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (136545021021613) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1845202986738 + ... + 1845202986811.
It is an arithmetic number, because the mean of its divisors is an integer number (35058856748725).
Almost surely, 2136545021021313 is an apocalyptic number.
It is an amenable number.
136545021021313 is a deficient number, since it is larger than the sum of its proper divisors (3690405973587).
136545021021313 is an equidigital number, since it uses as much as digits as its factorization.
136545021021313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3690405973586.
The product of its (nonzero) digits is 64800, while the sum is 37.
Adding to 136545021021313 its reverse (313120120545631), we get a palindrome (449665141566944).
The spelling of 136545021021313 in words is "one hundred thirty-six trillion, five hundred forty-five billion, twenty-one million, twenty-one thousand, three hundred thirteen".
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