Search a number
-
+
136545021021313 = 373690405973549
BaseRepresentation
bin11111000010111111011101…
…011110010100110010000001
3122220110120120021202101210101
4133002333131132110302001
5120344123200340140223
61202223530001002401
740522023624362242
oct3702773536246201
9586416507671711
10136545021021313
113a564466710803
121339340b323401
135b261a9124118
1425a0b58552cc9
1510bbcb18564ad
hex7c2fdd794c81

136545021021313 has 4 divisors (see below), whose sum is σ = 140235426994900. Its totient is φ = 132854615047728.

The previous prime is 136545021021187. The next prime is 136545021021329. The reversal of 136545021021313 is 313120120545631.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 122179154827024 + 14365866194289 = 11053468^2 + 3790233^2 .

It is a cyclic number.

It is not a de Polignac number, because 136545021021313 - 241 = 134345997765761 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (37), and also a Moran number because the ratio is a prime number: 3690405973549 = 136545021021313 / (1 + 3 + 6 + 5 + 4 + 5 + 0 + 2 + 1 + 0 + 2 + 1 + 3 + 1 + 3).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (136545021021613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1845202986738 + ... + 1845202986811.

It is an arithmetic number, because the mean of its divisors is an integer number (35058856748725).

Almost surely, 2136545021021313 is an apocalyptic number.

It is an amenable number.

136545021021313 is a deficient number, since it is larger than the sum of its proper divisors (3690405973587).

136545021021313 is an equidigital number, since it uses as much as digits as its factorization.

136545021021313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3690405973586.

The product of its (nonzero) digits is 64800, while the sum is 37.

Adding to 136545021021313 its reverse (313120120545631), we get a palindrome (449665141566944).

The spelling of 136545021021313 in words is "one hundred thirty-six trillion, five hundred forty-five billion, twenty-one million, twenty-one thousand, three hundred thirteen".

Divisors: 1 37 3690405973549 136545021021313