Base | Representation |
---|---|
bin | 111111100101111011… |
… | …0100011111011000010 |
3 | 111001111101101020120000 |
4 | 1333023312203323002 |
5 | 4214140400021223 |
6 | 142423041500430 |
7 | 12603120251001 |
oct | 1771366437302 |
9 | 431441336500 |
10 | 136564063938 |
11 | 52a09943565 |
12 | 22573041716 |
13 | cb54a96333 |
14 | 6877188c38 |
15 | 384426b543 |
hex | 1fcbda3ec2 |
136564063938 has 20 divisors (see below), whose sum is σ = 306004662150. Its totient is φ = 45521354592.
The previous prime is 136564063921. The next prime is 136564063949. The reversal of 136564063938 is 839360465631.
136564063938 is a `hidden beast` number, since 13 + 6 + 564 + 0 + 6 + 39 + 38 = 666.
It can be written as a sum of positive squares in only one way, i.e., 120830626449 + 15733437489 = 347607^2 + 125433^2 .
It is a Harshad number since it is a multiple of its sum of digits (54).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 421493863 + ... + 421494186.
Almost surely, 2136564063938 is an apocalyptic number.
136564063938 is a gapful number since it is divisible by the number (18) formed by its first and last digit.
136564063938 is an abundant number, since it is smaller than the sum of its proper divisors (169440598212).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
136564063938 is an equidigital number, since it uses as much as digits as its factorization.
136564063938 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 842988063 (or 842988054 counting only the distinct ones).
The product of its (nonzero) digits is 8398080, while the sum is 54.
The spelling of 136564063938 in words is "one hundred thirty-six billion, five hundred sixty-four million, sixty-three thousand, nine hundred thirty-eight".
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