Base | Representation |
---|---|
bin | 111111101000010100… |
… | …1100101111101110001 |
3 | 111001200222211101101021 |
4 | 1333100221211331301 |
5 | 4214322001104023 |
6 | 142435034535441 |
7 | 12605115341512 |
oct | 1772051457561 |
9 | 431628741337 |
10 | 136644550513 |
11 | 52a50317299 |
12 | 22595b97581 |
13 | cb68667023 |
14 | 6883b3aa09 |
15 | 384b36935d |
hex | 1fd0a65f71 |
136644550513 has 2 divisors, whose sum is σ = 136644550514. Its totient is φ = 136644550512.
The previous prime is 136644550397. The next prime is 136644550517. The reversal of 136644550513 is 315055446631.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 134298795024 + 2345755489 = 366468^2 + 48433^2 .
It is a cyclic number.
It is not a de Polignac number, because 136644550513 - 29 = 136644550001 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 136644550513.
It is not a weakly prime, because it can be changed into another prime (136644550517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68322275256 + 68322275257.
It is an arithmetic number, because the mean of its divisors is an integer number (68322275257).
Almost surely, 2136644550513 is an apocalyptic number.
It is an amenable number.
136644550513 is a deficient number, since it is larger than the sum of its proper divisors (1).
136644550513 is an equidigital number, since it uses as much as digits as its factorization.
136644550513 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648000, while the sum is 43.
The spelling of 136644550513 in words is "one hundred thirty-six billion, six hundred forty-four million, five hundred fifty thousand, five hundred thirteen".
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