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136644550513 is a prime number
BaseRepresentation
bin111111101000010100…
…1100101111101110001
3111001200222211101101021
41333100221211331301
54214322001104023
6142435034535441
712605115341512
oct1772051457561
9431628741337
10136644550513
1152a50317299
1222595b97581
13cb68667023
146883b3aa09
15384b36935d
hex1fd0a65f71

136644550513 has 2 divisors, whose sum is σ = 136644550514. Its totient is φ = 136644550512.

The previous prime is 136644550397. The next prime is 136644550517. The reversal of 136644550513 is 315055446631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 134298795024 + 2345755489 = 366468^2 + 48433^2 .

It is a cyclic number.

It is not a de Polignac number, because 136644550513 - 29 = 136644550001 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 136644550513.

It is not a weakly prime, because it can be changed into another prime (136644550517) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68322275256 + 68322275257.

It is an arithmetic number, because the mean of its divisors is an integer number (68322275257).

Almost surely, 2136644550513 is an apocalyptic number.

It is an amenable number.

136644550513 is a deficient number, since it is larger than the sum of its proper divisors (1).

136644550513 is an equidigital number, since it uses as much as digits as its factorization.

136644550513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648000, while the sum is 43.

The spelling of 136644550513 in words is "one hundred thirty-six billion, six hundred forty-four million, five hundred fifty thousand, five hundred thirteen".