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1367131841441 is a prime number
BaseRepresentation
bin10011111001001111011…
…010000110001110100001
311211200210202202100012222
4103321033122012032201
5134344341222411231
62524015100000425
7200525541625622
oct23711732061641
94750722670188
101367131841441
11487885313293
121a0b61830115
139bbc626c242
144a2532b7a49
152586783627b
hex13e4f6863a1

1367131841441 has 2 divisors, whose sum is σ = 1367131841442. Its totient is φ = 1367131841440.

The previous prime is 1367131841431. The next prime is 1367131841447. The reversal of 1367131841441 is 1441481317631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1271075856400 + 96055985041 = 1127420^2 + 309929^2 .

It is an emirp because it is prime and its reverse (1441481317631) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1367131841441 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1367131841392 and 1367131841401.

It is not a weakly prime, because it can be changed into another prime (1367131841447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 683565920720 + 683565920721.

It is an arithmetic number, because the mean of its divisors is an integer number (683565920721).

Almost surely, 21367131841441 is an apocalyptic number.

It is an amenable number.

1367131841441 is a deficient number, since it is larger than the sum of its proper divisors (1).

1367131841441 is an equidigital number, since it uses as much as digits as its factorization.

1367131841441 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 193536, while the sum is 44.

The spelling of 1367131841441 in words is "one trillion, three hundred sixty-seven billion, one hundred thirty-one million, eight hundred forty-one thousand, four hundred forty-one".