Base | Representation |
---|---|
bin | 1100011100000011011111… |
… | …0111110001100110101011 |
3 | 1210102102102211211201020221 |
4 | 3013000313313301212223 |
5 | 3243032134442112233 |
6 | 45030415241430511 |
7 | 2611031556324565 |
oct | 307006767614653 |
9 | 53372384751227 |
10 | 13676113238443 |
11 | 43a3009429937 |
12 | 164a63279b437 |
13 | 782862426406 |
14 | 353cdab6a335 |
15 | 18ab3166a42d |
hex | c7037df19ab |
13676113238443 has 4 divisors (see below), whose sum is σ = 14009676976008. Its totient is φ = 13342549500880.
The previous prime is 13676113238377. The next prime is 13676113238503. The reversal of 13676113238443 is 34483231167631.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13676113238443 - 221 = 13676111141291 is a prime.
It is a super-3 number, since 3×136761132384433 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13676113230443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 166781868721 + ... + 166781868802.
It is an arithmetic number, because the mean of its divisors is an integer number (3502419244002).
Almost surely, 213676113238443 is an apocalyptic number.
13676113238443 is a deficient number, since it is larger than the sum of its proper divisors (333563737565).
13676113238443 is an equidigital number, since it uses as much as digits as its factorization.
13676113238443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 333563737564.
The product of its digits is 5225472, while the sum is 52.
The spelling of 13676113238443 in words is "thirteen trillion, six hundred seventy-six billion, one hundred thirteen million, two hundred thirty-eight thousand, four hundred forty-three".
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