Base | Representation |
---|---|
bin | 10011111010101001100… |
… | …000001111011010010001 |
3 | 11211211201010000112121201 |
4 | 103322221200033122101 |
5 | 134410440202320421 |
6 | 2524425053551201 |
7 | 200611154651065 |
oct | 23725140173221 |
9 | 4754633015551 |
10 | 1368643401361 |
11 | 488490579665 |
12 | 1a1303aa5501 |
13 | 9c0a747b0b2 |
14 | 4a357d49aa5 |
15 | 259053b5b91 |
hex | 13ea980f691 |
1368643401361 has 2 divisors, whose sum is σ = 1368643401362. Its totient is φ = 1368643401360.
The previous prime is 1368643401271. The next prime is 1368643401439. The reversal of 1368643401361 is 1631043468631.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1363663417600 + 4979983761 = 1167760^2 + 70569^2 .
It is a cyclic number.
It is not a de Polignac number, because 1368643401361 - 29 = 1368643400849 is a prime.
It is not a weakly prime, because it can be changed into another prime (1368643431361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 684321700680 + 684321700681.
It is an arithmetic number, because the mean of its divisors is an integer number (684321700681).
Almost surely, 21368643401361 is an apocalyptic number.
It is an amenable number.
1368643401361 is a deficient number, since it is larger than the sum of its proper divisors (1).
1368643401361 is an equidigital number, since it uses as much as digits as its factorization.
1368643401361 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 746496, while the sum is 46.
Adding to 1368643401361 its reverse (1631043468631), we get a palindrome (2999686869992).
The spelling of 1368643401361 in words is "one trillion, three hundred sixty-eight billion, six hundred forty-three million, four hundred one thousand, three hundred sixty-one".
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