Base | Representation |
---|---|
bin | 11001011111111010… |
… | …11100011011100001 |
3 | 1022100001021121011001 |
4 | 30233331130123201 |
5 | 211014010211043 |
6 | 10142222152001 |
7 | 663145104205 |
oct | 145775343341 |
9 | 38301247131 |
10 | 13689538273 |
11 | 58954297a4 |
12 | 27a0722601 |
13 | 13a21ba308 |
14 | 93c17cb05 |
15 | 551c5974d |
hex | 32ff5c6e1 |
13689538273 has 2 divisors, whose sum is σ = 13689538274. Its totient is φ = 13689538272.
The previous prime is 13689538259. The next prime is 13689538301. The reversal of 13689538273 is 37283598631.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13556643489 + 132894784 = 116433^2 + 11528^2 .
It is a cyclic number.
It is not a de Polignac number, because 13689538273 - 25 = 13689538241 is a prime.
It is not a weakly prime, because it can be changed into another prime (13689538223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6844769136 + 6844769137.
It is an arithmetic number, because the mean of its divisors is an integer number (6844769137).
Almost surely, 213689538273 is an apocalyptic number.
It is an amenable number.
13689538273 is a deficient number, since it is larger than the sum of its proper divisors (1).
13689538273 is an equidigital number, since it uses as much as digits as its factorization.
13689538273 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6531840, while the sum is 55.
The spelling of 13689538273 in words is "thirteen billion, six hundred eighty-nine million, five hundred thirty-eight thousand, two hundred seventy-three".
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