Base | Representation |
---|---|
bin | 11111001000001010000001… |
… | …011000110010000010101001 |
3 | 122221201111201110221212211112 |
4 | 133020022001120302002221 |
5 | 120420432103314144433 |
6 | 1203054550031440105 |
7 | 40556460406033616 |
oct | 3710120130620251 |
9 | 587644643855745 |
10 | 136899958349993 |
11 | 3a690a45572183 |
12 | 13430167086035 |
13 | 5b507c287a4b7 |
14 | 25b3dc9a1150d |
15 | 10c6137082348 |
hex | 7c82816320a9 |
136899958349993 has 2 divisors, whose sum is σ = 136899958349994. Its totient is φ = 136899958349992.
The previous prime is 136899958349923. The next prime is 136899958350013. The reversal of 136899958349993 is 399943859998631.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 102093887639104 + 34806070710889 = 10104152^2 + 5899667^2 .
It is a cyclic number.
It is not a de Polignac number, because 136899958349993 - 240 = 135800446722217 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 136899958349896 and 136899958349905.
It is not a weakly prime, because it can be changed into another prime (136899958349923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68449979174996 + 68449979174997.
It is an arithmetic number, because the mean of its divisors is an integer number (68449979174997).
Almost surely, 2136899958349993 is an apocalyptic number.
It is an amenable number.
136899958349993 is a deficient number, since it is larger than the sum of its proper divisors (1).
136899958349993 is an equidigital number, since it uses as much as digits as its factorization.
136899958349993 is an evil number, because the sum of its binary digits is even.
The product of its digits is 110199605760, while the sum is 95.
The spelling of 136899958349993 in words is "one hundred thirty-six trillion, eight hundred ninety-nine billion, nine hundred fifty-eight million, three hundred forty-nine thousand, nine hundred ninety-three".
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