Base | Representation |
---|---|
bin | 111111110000111110… |
… | …0010110011001011001 |
3 | 111002110012202111102111 |
4 | 1333201330112121121 |
5 | 4220420234231103 |
6 | 142523521232321 |
7 | 12615240401515 |
oct | 1774174263131 |
9 | 432405674374 |
10 | 136934680153 |
11 | 5308a069a57 |
12 | 226571926a1 |
13 | cbb37ba27b |
14 | 68b04a1145 |
15 | 3866a7886d |
hex | 1fe1f16659 |
136934680153 has 2 divisors, whose sum is σ = 136934680154. Its totient is φ = 136934680152.
The previous prime is 136934680147. The next prime is 136934680163. The reversal of 136934680153 is 351086439631.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 119680018704 + 17254661449 = 345948^2 + 131357^2 .
It is an emirp because it is prime and its reverse (351086439631) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 136934680153 - 29 = 136934679641 is a prime.
It is a super-2 number, since 2×1369346801532 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 136934680097 and 136934680106.
It is not a weakly prime, because it can be changed into another prime (136934680123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68467340076 + 68467340077.
It is an arithmetic number, because the mean of its divisors is an integer number (68467340077).
Almost surely, 2136934680153 is an apocalyptic number.
It is an amenable number.
136934680153 is a deficient number, since it is larger than the sum of its proper divisors (1).
136934680153 is an equidigital number, since it uses as much as digits as its factorization.
136934680153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1399680, while the sum is 49.
The spelling of 136934680153 in words is "one hundred thirty-six billion, nine hundred thirty-four million, six hundred eighty thousand, one hundred fifty-three".
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