Base | Representation |
---|---|
bin | 10011111011101001010… |
… | …101101100111110010001 |
3 | 11211221110202020221001202 |
4 | 103323221111230332101 |
5 | 134420133340140224 |
6 | 2525123232440545 |
7 | 200646541064564 |
oct | 23735125547621 |
9 | 4757422227052 |
10 | 1369714380689 |
11 | 488990072246 |
12 | 1a15626a9155 |
13 | 9c21830a785 |
14 | 4a41a2924db |
15 | 25969417eae |
hex | 13ee956cf91 |
1369714380689 has 2 divisors, whose sum is σ = 1369714380690. Its totient is φ = 1369714380688.
The previous prime is 1369714380647. The next prime is 1369714380721. The reversal of 1369714380689 is 9860834179631.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 956059595089 + 413654785600 = 977783^2 + 643160^2 .
It is a cyclic number.
It is not a de Polignac number, because 1369714380689 - 228 = 1369445945233 is a prime.
It is a super-2 number, since 2×13697143806892 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1369714380889) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 684857190344 + 684857190345.
It is an arithmetic number, because the mean of its divisors is an integer number (684857190345).
Almost surely, 21369714380689 is an apocalyptic number.
It is an amenable number.
1369714380689 is a deficient number, since it is larger than the sum of its proper divisors (1).
1369714380689 is an equidigital number, since it uses as much as digits as its factorization.
1369714380689 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 47029248, while the sum is 65.
The spelling of 1369714380689 in words is "one trillion, three hundred sixty-nine billion, seven hundred fourteen million, three hundred eighty thousand, six hundred eighty-nine".
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