Base | Representation |
---|---|
bin | 110100010000… |
… | …000010000001 |
3 | 221202212221222 |
4 | 310100002001 |
5 | 12001302103 |
6 | 1205324425 |
7 | 224265251 |
oct | 64200201 |
9 | 27685858 |
10 | 13697153 |
11 | 7805968 |
12 | 4706715 |
13 | 2ab7632 |
14 | 1b67961 |
15 | 1308638 |
hex | d10081 |
13697153 has 4 divisors (see below), whose sum is σ = 13747968. Its totient is φ = 13646340.
The previous prime is 13697149. The next prime is 13697197. The reversal of 13697153 is 35179631.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35179631 = 293 ⋅120067.
It is a cyclic number.
It is not a de Polignac number, because 13697153 - 22 = 13697149 is a prime.
It is a super-2 number, since 2×136971532 = 375224000610818, which contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13697113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25001 + ... + 25542.
It is an arithmetic number, because the mean of its divisors is an integer number (3436992).
Almost surely, 213697153 is an apocalyptic number.
It is an amenable number.
13697153 is a deficient number, since it is larger than the sum of its proper divisors (50815).
13697153 is an equidigital number, since it uses as much as digits as its factorization.
13697153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50814.
The product of its digits is 17010, while the sum is 35.
The square root of 13697153 is about 3700.9664953901. The cubic root of 13697153 is about 239.2636749626.
The spelling of 13697153 in words is "thirteen million, six hundred ninety-seven thousand, one hundred fifty-three".
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