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1369950433 is a prime number
BaseRepresentation
bin101000110100111…
…1100100011100001
310112110210200200221
41101221330203201
510301201403213
6343534443041
745643246405
oct12151744341
93473720627
101369950433
11643335045
12322963481
1318aa8a077
14cdd2d105
158040b38d
hex51a7c8e1

1369950433 has 2 divisors, whose sum is σ = 1369950434. Its totient is φ = 1369950432.

The previous prime is 1369950409. The next prime is 1369950437. The reversal of 1369950433 is 3340599631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 874798929 + 495151504 = 29577^2 + 22252^2 .

It is an emirp because it is prime and its reverse (3340599631) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1369950433 - 213 = 1369942241 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1369950433.

It is not a weakly prime, because it can be changed into another prime (1369950437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 684975216 + 684975217.

It is an arithmetic number, because the mean of its divisors is an integer number (684975217).

Almost surely, 21369950433 is an apocalyptic number.

It is an amenable number.

1369950433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1369950433 is an equidigital number, since it uses as much as digits as its factorization.

1369950433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 262440, while the sum is 43.

The square root of 1369950433 is about 37012.8414607687. The cubic root of 1369950433 is about 1110.6271468821.

The spelling of 1369950433 in words is "one billion, three hundred sixty-nine million, nine hundred fifty thousand, four hundred thirty-three".