Base | Representation |
---|---|
bin | 11001100001011011… |
… | …00001010111111001 |
3 | 1022100220222220102202 |
4 | 30300231201113321 |
5 | 211030222011213 |
6 | 10143352235545 |
7 | 663360165131 |
oct | 146055412771 |
9 | 38326886382 |
10 | 13702141433 |
11 | 58a1557732 |
12 | 27a499bbb5 |
13 | 13a49b09c6 |
14 | 93daddac1 |
15 | 552de8b58 |
hex | 330b615f9 |
13702141433 has 2 divisors, whose sum is σ = 13702141434. Its totient is φ = 13702141432.
The previous prime is 13702141429. The next prime is 13702141471. The reversal of 13702141433 is 33414120731.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13195576384 + 506565049 = 114872^2 + 22507^2 .
It is a cyclic number.
It is not a de Polignac number, because 13702141433 - 22 = 13702141429 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13702141396 and 13702141405.
It is not a weakly prime, because it can be changed into another prime (13702141483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6851070716 + 6851070717.
It is an arithmetic number, because the mean of its divisors is an integer number (6851070717).
Almost surely, 213702141433 is an apocalyptic number.
It is an amenable number.
13702141433 is a deficient number, since it is larger than the sum of its proper divisors (1).
13702141433 is an equidigital number, since it uses as much as digits as its factorization.
13702141433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 29.
The spelling of 13702141433 in words is "thirteen billion, seven hundred two million, one hundred forty-one thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •