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13702340703433 is a prime number
BaseRepresentation
bin1100011101100101001100…
…1001100111010011001001
31210111221010200102222111011
43013121103021213103021
53243444343210002213
645050433551203521
72612650530154234
oct307312311472311
953457120388434
1013702340703433
114403148120538
1216537322165a1
1378518204c275
143552a815241b
1518b668ea103d
hexc76532674c9

13702340703433 has 2 divisors, whose sum is σ = 13702340703434. Its totient is φ = 13702340703432.

The previous prime is 13702340703419. The next prime is 13702340703487. The reversal of 13702340703433 is 33430704320731.

13702340703433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13700339751609 + 2000951824 = 3701397^2 + 44732^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13702340703433 is a prime.

It is a super-2 number, since 2×137023407034332 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13702340703413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6851170351716 + 6851170351717.

It is an arithmetic number, because the mean of its divisors is an integer number (6851170351717).

Almost surely, 213702340703433 is an apocalyptic number.

It is an amenable number.

13702340703433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13702340703433 is an equidigital number, since it uses as much as digits as its factorization.

13702340703433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 381024, while the sum is 40.

The spelling of 13702340703433 in words is "thirteen trillion, seven hundred two billion, three hundred forty million, seven hundred three thousand, four hundred thirty-three".