Base | Representation |
---|---|
bin | 10011111100011011011… |
… | …101000000011001010011 |
3 | 11212000122100022202000222 |
4 | 103330123131000121103 |
5 | 134423344104443201 |
6 | 2525342505303255 |
7 | 201006430415654 |
oct | 23743335003123 |
9 | 4760570282028 |
10 | 1370555156051 |
11 | 489281723214 |
12 | 1a1758194b2b |
13 | 9c3205690a3 |
14 | 4a499bd352b |
15 | 259b814691b |
hex | 13f1b740653 |
1370555156051 has 2 divisors, whose sum is σ = 1370555156052. Its totient is φ = 1370555156050.
The previous prime is 1370555156041. The next prime is 1370555156063. The reversal of 1370555156051 is 1506515550731.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1370555156051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1370555155993 and 1370555156011.
It is not a weakly prime, because it can be changed into another prime (1370555156041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 685277578025 + 685277578026.
It is an arithmetic number, because the mean of its divisors is an integer number (685277578026).
Almost surely, 21370555156051 is an apocalyptic number.
1370555156051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1370555156051 is an equidigital number, since it uses as much as digits as its factorization.
1370555156051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 393750, while the sum is 44.
The spelling of 1370555156051 in words is "one trillion, three hundred seventy billion, five hundred fifty-five million, one hundred fifty-six thousand, fifty-one".
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